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Answer :

`x = -2`Solution :

`(x^(2) _ 3x + 2)/(x^(2) - 6x - 7) = 0 or((x+ 1)(x+2))/((x-7)(x+ 1)) = 0` is solvable over R - {7, -1} <br> Hence, from given equation, x = -2, which is the only roots of the equation. **What is Real polynomial, complex polynomial and degree of a polynomial?**

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